Answer to Question #319332 in Chemistry for Shekinah Ann Erika

Question

A container with a volume of 14 L filled with gas at 2.00 atm at 283k. What will be the new pressure temperature increase to 321k? 

Answer 1

P₁ = 2.00 atm

T₁ = 283 K

V₁ = V₂ = 14 L = constant

P₂ = ???

T₂ = 321 K

Solution:

Since the volume and amount of gas remain unchanged, Gay-Lussac's law can be used.

Gay-Lussac's law can be expressed as: P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

To find the new pressure, solve the equation for P₂:

P₂ = P₁T₂/T₁

P₂ = (2.00 atm × 321 K) / (283 K) = 2.27 atm

P₂ = 2.27 atm

Answer: The new pressure will be 2.27 atm