Answer to Question #319150 in Chemistry for kelly

Question

4. Consider the following reaction: C12H22O11(s) -----------> HH2O(g) + 12C(s). The rate of decomposition of C12H22O11 is 0.75 mol/min. What mass of C is produced in 10 seconds?

Answer 1

The amount of C₁₂H₂₂O₁₁ used in 10 seconds is: 0.75 / 60 x10 = 0.125 mol

According to the equation, 1 mole of C₁₂H₂₂O₁₁ results in 12 moles of C:

n (C) = 0.125 x 12 = 1.5 mol

n = m / M

M (C) = 12 g/mol

m (C) = n x C = 1.5 x 12 = 18 g