Answer to Question #297161 in Chemistry for Victoria

Question

ii) Calculate the concentration of methanol produced by the reaction in (b), with the

following reactant concentrations:

CO: 2.13 x 10-3 mol L-1

H2: 1.4 x 10-3 mol L-1

Answer 1

Solution:

C_M(CO) = 2.13×10^-3 M

C_M(H₂) = 1.40×10^-3 M

Balanced chemical equation:

CO(g) + 2H₂(g) ⇌ CH₃OH(g)

ICE Table:

Therefore,

[CH₃OH] = 0.70×10^-3 M = 0.70×10^-3 mol L^-1

Answer: The concentration of methanol (CH₃OH) is 0.70×10^-3 mol L^-1