How many moles of carbon are in 333 mg of CaC2O4.
Solution:
The molar mass of CaC2O4 is 128.097 g/mol
Hence,
(333 mg CaC2O4) × (1 g / 1000 mg) × (1 mol CaC2O4 / 128.097 g CaC2O4) = 0.0026 mol CaC2O4
Moles of CaC2O4 = 0.0026 mol
1 mol of CaC2O4 contains 2 mol of C
Thus, 0.0026 mol of CaC2O4 contains:
(0.0026 mol CaC2O4) × (2 mol C / 1 mol CaC2O4) = 0.0052 mol C
Moles of C = 0.0052 mol
Answer: 0.0052 moles of carbon
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