Answer to Question #297032 in Chemistry for Zoe

Question

Find the number of Na+ ions in 2.92 g of Na3PO4

Answer 1

Solution:

The molar mass of Na₃PO₄ is 163.94 g/mol

Hence,

Moles of Na₃PO₄ = (2.92 g Na₃PO₄) × (1 mol Na₃PO₄ / 163.94 g Na₃PO₄) = 0.0178 mol Na₃PO₄

Na₃PO₄ → 3Na⁺ + PO₄^3-

Hence,

1 mol of Na₃PO₄ contains 3 mol of Na⁺ ions

Thus, 0.0178 mol of Na₃PO₄ contains:

(0.0178 mol Na₃PO₄) × (3 mol Na⁺ ions / 1 mol Na₃PO₄) = 0.0534 mol Na⁺ ions

One mole of any substance contains 6.022×10²³ particles.

Hence,

Number of Na⁺ ions = (0.0534 mol) × (6.022×10²³ ions / 1 mol) = 3.216×10²² ions

Answer: 3.216×10²² of Na⁺ ions