Answer to Question #292963 in Chemistry for bob

Question

At 200.0 K, a gas fills a 475.0 mL balloon. What will be the volume of the balloon if the temperature is raised by 60.0 K?

Answer 1

T₁ = 200.0 K

V₁ = 475.0 mL

P₁ = P₂ = const

T₂ = 200.0 K + 60.0 K = 260.0 K

V₂ = unknown

Solution:

Since the pressure doesn't change, Charles' Law can be used.

Charles' Law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the new volume, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (475.0 mL × 260.0 K) / (200.0 K) = 617.5 mL

V₂ = 617.5 mL

Answer: The volume of the balloon will be 617.5 mL