What is the mass percentage of O in C₃H₈O₂?
M (C₃H₈O₂) = 76.1 g/mol
M (C) = 12 g/mol
M (H) = 1 g/mol
M (O) = 16 g/mol
%(O) = (100 x (16 x 2)) / 76.1 = 42%
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