• what is the mass in grams of 1.204 x 10²³ molecules of H2O?
• how many formula units are there in 0.175 g of LiF
Solution:
(1):
One mole of any substance contains 6.022×1023 particles.
Therefore,
Moles of H2O = (1.204×1023 molecules) × (1 mol / 6.022×1023 molecules) = 0.1999 mol = 0.2 mol
The molar mass of H2O is 18.0153 g/mol
Therefore,
Mass of H2O = (0.2 mol H2O) × (18.0153 g H2O / 1 mol H2O) = 3.603 g H2O = 3.6 g H2O
Answer (1): 3.6 grams of H2O
(2):
The molar mass of LiF is 25.94 g/mol
Therefore,
Moles of LiF = (0.175 g LiF) × (1 mol LiF / 25.94 g LiF) = 0.00675 mol LiF
One mole of any substance contains 6.022×1023 particles.
Therefore,
Formula units of LiF = (0.00675 mol) × (6.022×1023 formula units / 1 mol) = 4.065×1021 formula units
Answer (2): 4.065×1021 formula units LiF
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