Answer to Question #286480 in Chemistry for khryst

Question

1.     What would be the solubility product constant (K_sp) equation for a theoretical compound X₃Y?

a.      K_sp = 3 [X⁺] [Y³⁻]

b.     K_sp = [X⁺]³ [Y³⁻]

c.      K_sp = [X⁺] [Y³⁻]³

d.     K_sp = ⅓ [X⁺] [Y³⁻]

 

2.     What would be the solubility product constant (K_sp) equation for a theoretical compound XY₂?

a.      K_sp = [X²⁺] ½ [Y⁻]

b.     K_sp = [X²⁺] 2 [Y⁻]

c.      K_sp = [X²⁺] [Y⁻]²

d.     K_sp = [X²⁺] 2 [Y⁻]

 

3.     What would be the solubility product constant (K_sp) equation for a theoretical compound X₂Y₃?

Answer 1

Solution:

(1):

The K_sp expression for X₃Y(s) is:

X₃Y(s) ⇌ 3X⁺(aq) + Y³⁻(aq)

Thus,

K_sp(X₃Y) = [X⁺]³ [Y³⁻]

Answer (1):

b) K_sp = [X⁺]³ [Y³⁻]

(2):

The K_sp expression for XY₂(s) is:

XY₂(s) ⇌ X²⁺(aq) + 2Y⁻(aq)

Thus,

K_sp(XY₂) = [X²⁺] [Y⁻]²

Answer (2):

c) K_sp = [X²⁺] [Y⁻]²

(3):

The K_sp expression for X₂Y₃(s) is:

X₂Y₃(s) ⇌ 2X³⁺(aq) + 3Y²⁻(aq)

Thus,

K_sp(XY₂) = [X³⁺]² [Y²⁻]³

Answer (3):

K_sp = [X³⁺]² [Y²⁻]³