The sides of a triangle measuring 40 m, 32 m, and 16 m increase at the rates of 2 m/s, 5 m/s, and 3 m/s, respectively. How fast is the area of the triangle changing?
a. 138.42 m^2/s
b. 113.69 m/s
c. 127.33 m^2/s
d. 113.69 m^2/s
S = (p x (p-a) x (p-b) x (p-c))1/2
p1 = (a + b + c) / 2 = (40 + 32 + 16) / 2 = 44
S1 = (44 x (44-40) x (44-32) x (44-16))1/2 = 243.2 cm2
p2 = (42 + 37 + 19)/2 = 49
S2 = (49 x (49-42) x (49-37) x (49-19))1/2 = 351.4 m2
deltaS = 351.4 - 243.2 = 113.7 m2
Answer d. 113.69 m2/s
Comments
Leave a comment