Answer to Question #286334 in Chemistry for neo

Question

A container contains 2.5m ³ of Helium gas at 15 ⁰ C and 98 Nm -2 pressures. What volume would this gas occupy at S.T.P? 

Answer 1

The standard temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure.

pV = nRT

n = pV / RT

1 Pa = 1 Nm

R = 8.31432×10³ N⋅m⋅kmol⁻¹⋅K⁻¹ = 8.31432 m³⋅Pa⋅K⁻¹⋅mol⁻¹

n (He) = 98 x 2.5 / (8.314 x (15+273)) = 0.10 mol

V (He)_stp= nRT / p = (0.10 x 8.314 x 273) / 1 = 222 m³