Answer to Question #285688 in Chemistry for neg

Question

Ni(CNi42 + 2AgBr(i)  2Ag(C 2 + Ni²+ + 2Br°

The liberated nickel ion required 26.73 mL of 0.02089 M EDTA. The bromate in a 10.00-mL aliquot was 

reduced to bromide with arsenic(UI) priof to the addition of silver nitrate. The same procedure 

was followed, and the released nickel ion was titrated with 21.94 mL of the EDTA solution. 

Calculate the percentages of NaBr and NaBrO3 in the sample.

Answer 1

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