Zinc reacts with element X to form a compound used as rat poison. In a chemical analysis, it is found that 3.90g zinc combines with 1.24g X to form the compound with empirical formula Zn3X2. Determine the relative atomic mass of element X.
[Relative atomic mass: Zn, 65]
Solution:
Calculate the moles of Zn:
The molar mass of Zn is 65 g/mol
Therefore,
(3.90 g Zn) × (1 mol Zn / 65 g Zn) = 0.06 mol Zn
Balanced chemical equation:
3Zn + 2X → Zn3X2
According to stoichiometry:
3 moles of Zn reacts with 2 moles of X
Thus 0.06 moles of Zn reacts with:
(0.06 mol Zn) × (2 mol X / 3 mol Zn) = 0.04 mol X
Calculate the relative atomic mass of element X:
(1.24 g X) / (0.04 mol X) = 31 g/mol - phosphorus (P)
Zn3X2 = Zn3P2
The relative atomic mass of element X is 31
Answer: The relative atomic mass of element X is 31
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