Seven and one-fourth tons of compost containing 2.1 % N, 1.15 % P2O5, and 0.97% K2O can supply how many kilograms of N, P2O5, P and K2O & K ?
m (N) = 7 250 kg x 0.021 = 152.25 kg
m (P2O5) = 7 250 kg x 0.0115 = 83.375 kg
m (K2O) = 7 250 kg x 0.0097 = 70.325 kg
Comments
Leave a comment