A combustion process of a 100 mol of solid mineral with 325 mole of pure oxygen is
producing ferric oxide and sulfur trioxide gases. The solid mineral contains of 82 mole% iron
pyrites (FeS2) and 18 mole% inerts.
a) Write the chemical equation for the combustion process.
b) Calculate;
i.
The limiting reactant.
ii.
The percentage of excess.
iii.
The extent of reaction, ξ if complete reaction occurred
2FeS2 + 7O2 = 2FeO + 4SO3
1) According to the equation, 2 moles of FeS2 require 7 moles of O2. Therefore,
82 moles of iron pyrites (FeS2) require: n (O2) = 7 x n (FeS2) / 2 = 287 moles.
According to this, FeS2 is the limiting reactant, O2 is in excess.
2) n (O2)excess = 325 - 287 = 38 moles
n (O2)%excess = 38 / 287 x 100 = 13.2%
3) Extent of reaction is a quantity that measures the extent to which the reaction proceeds.
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