Answer to Question #202598 in Chemistry for kim

Question

1.   Ten grams of plastic beads with a density of 1.2 g/cm3 are added to 500 ml of an organic solvent with a density of 0.80 g/cm3. What is the concentration of plastic beads in mg/L?

Answer 1

Solution:

Mass of plastic beads = 10 g

Volume of plasctic beads = (10 g) / (1.2 g cm^-3) = 8.33 cm³ = 8.33 mL

Volume of organic solvent = 500 mL

Volume of solution = 8.33 mL + 500 mL = 508.33 mL = 0.50833 L = 0.508 L

Therefore,

Concentration of plastic beads = (10 g) × (1000 mg / 1 g) × (1 / 0.508 L) = 19685 mg/L

Concentration of plastic beads = 19685 mg/L

Answer: The concentration of plastic beads is 19685 mg/L.