96.3 g of potassium iodate (KIO3) is used to prepare 300.0 mL of solution. What is the molar concentration of the solution?
Solution:
The molar mass of KIO3 is 214 g/mol.
Therefore,
(96.3 g KIO3) × (1 mol KIO3 / 214 g KIO3) = 0.45 mol KIO3
Molarity is defined as number of moles of solute dissolved in 1 L of solution.
Therefore,
Molarity = (0.45 mol / 0.3 L) = 1.5 mol/L
Molarity = 1.5 mol/L
Answer: The molar concentration of the solution is 1.5 mol/L
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