Answer to Question #188777 in Chemistry for faith

Question

if 86.1 g of nitrogen reacts with lithium, how many grams of lithium will react

Answer 1

Solution:

Balanced chemical equation:

6Li + N₂ → 2Li₃N

According to the equation above: n(Li)/6 = n(N₂)

The molar mass of N₂ is 28.013 g/mol.

Hence,

n(N₂) = (86.1 g N₂) × (1 mol N₂ / 28.013 g N₂) = 3.07357 mol N₂

n(Li) = 6 × n(N₂) = 6 × 3.07357 mol = 18.44 mol Li

The molar mass of Li is 6.941 g/mol.

Hence,

m(Li) = (18.44 mol Li) × (6.941 g Li / 1 mol Li) = 127.992 g Li = 128 g Li

Mass of Li = 128 g

OR (short form soluion):

(86.1 g N₂) × (1 mol N₂ / 28.013 g N₂) × (6 mol Li / 1 mol N₂) × (6.941 g Li / 1 mol Li) = 128.0 g of Li

Answer: 128.0 grams of lithium (Li) will react.