Answer to Question #187678 in Chemistry for Oscar

Question #187678

If you have 56 grams of O₂that react with NH_3,how many moles H₂0 will be produced?

Expert's answer

4NH₃ + 3O₂ = 6H₂O + 2N₂

n = m / M

M (O₂) = 32 g/mol

M (H₂O) = 18 g/mol

n (O₂) = 56 / 32 = 1.75 mol

According to the equation, n (H₂O) = 6/3 x n(O₂) = 2 x 1.75 = 3.5 mol

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