Calculate the mass of hydrogen formed when 30 grams of aluminum reacts with excess hydrochloric acid according to the balanced equation below:
2Al + 6HCl --> 2AlCl3 + 3H2
n = m / M
M (Al) = 27 g/mol
M (H2) = 2 g/mol
n (Al) = 30 / 27 = 1.1 mol
According to the equation, n (H2) = 3/2 x n (Al) = 3/2 x 1.1 = 1.7 mol
m (H2) = n x M = 1.7 x 2 = 3.4 g
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