Answer to Question #170705 in Chemistry for Hyeri

Question

How much 0.1 F HCl is required to make 300 ml of solution with a pH of 1.8

Answer 1

HCl is a strong acid, it dissociates in the water environment completely.

pH = - lg [H⁺]

1.8 = - lg [H⁺]

H⁺ = 6.05

Therefore, the concentration C_M (HCl) = 6.05 mol/l

n₁=n₂

C_M = n/V

n = C_M x V

6.05 x V = 0.1 x 0.3

V = (0.1 x 0.3) / 6.05 = 0.005 L