Calculate the pH of a 0.1 F solution of NaHSO4.
NaHSO4 dissociates as follows:
NaHSO4 = Na+ + HSO4-
HSO4- = H+ + SO42-
Ka = [H+][SO42-] / [NaHSO4]
[H+][SO42-] = [NaHSO4] × Ka = 0.1 F × 1.2 × 10-2 = 0.0012 F2
[H+] = 0.035 F
pH = -log[H+] = 2.92
Answer: 2.92
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