What is the hydronium-ion concentration of a 0.03 F HCN solution?
According to the equation:
Ka = [H+][CN-] / [HCN]
From here:
[H+][CN-] = Ka × [HCN]
[H+]² = Ka × [HCN]
[H+] = (Ka × [HCN])1/2 = 4.5 × 10-10 × 0.03 F = 3.7 × 10-4 F
Answer: 3.7 × 10-4 F
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