Answer to Question #170657 in Chemistry for Vavine GI

Question

Suppose 9.00 mol of hydrogen reacted with sufficient nitrogen. How many moles of ammonia would be produced?

Answer 1

Solution:

The balanced chemical equation:

3H₂ + N₂ → 2NH₃

According to the equation above: n(H₂)/3 = n(NH₃)/2

Hence,

n(NH₃) = 2 × n(H₂) / 3

n(NH₃) = (2 × 9.00 mol) / 3 = 6.00 mol

n(NH₃) = 6.00 mol

Answer: 6.00 mol of ammonia (NH₃) would be produced.