What concentration of hydroxide ions exist in a 0.008 F solution of NH3 at 25°C .
In solution, NH3 dissociates as follows:
NH3 + H2O = NH4+ + OH-
Dissociation constant:
Kb = [NH4+][OH-] / [NH3]
From here:
[OH-] = [NH4+] = (Kb × [NH3])1/2 = (1.8 × 10-5 × 0.008 F) = 3.8 × 10-4 F
Answer: 3.8 × 10-4 F
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