Answer to Question #167955 in Chemistry for Ava Brooke

Question

If 19.22 grams of aluminum is heated from 15 ^oC to 50 ^oC how much energy was required?

s_Al = 0.897 J/(gK)

Answer 1

Solution:

q = m × C × ΔT

q = m × C × (T_f - T_i),

where:

q = amount of heat energy gained or lost by substance

m = mass of sample

C = specific heat capacity (J ^oC^-1 g^-1)

T_f = final temperature

T_i = initial temperature

 

Thus:

q = (19.22 g) × (0.897 J ^oC^-1 g^-1) × (50 - 15)^oC = 603.4 J

q = 603.4 J (or 0.6 kJ)

Answer: 603.4 Joules of energy was required.