What is the [H3O-] and [OH-] ion concentration respectively in a solution that contains 0.155 M HNO3?
Solution:
HNO3 + H2O → H3O+ + NO3-
After complete dissociation: CM(HNO3) = [H3O+] = [NO3-]
So concentration of [H3O+] = 0.155 M
[H3O+] = 0.155 M
For any aqueous solution at 25∘C:
Kw = [H3O+] × [OH-] = 1×10-14
Hence,
[OH-] = Kw / [H3O+]
[OH-] = (1×10-14) / (0.155) = 6.45×10-14
[OH-] = 6.45×10-14 M
Answer: [H3O+] = 0.155 M; [OH-] = 6.45×10-14 M.
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