Determine the mass in grams of Li+ (6.941 g/mol) in 25.0 g of Li2SO4 (109.94 g/mol)
The compound dissociates as the following:
Li2SO4 = 2Li+ + SO42-
From here, the mass of lithium ions equals:
m(Li+) = m(Li2SO4) × 2 × Mr(Li+) / Mr(Li2SO4) = 25.0 g × 2 × 6.941 g/mol / 109.94 g/mol = 3.16 g
Answer: 3.16 g
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