How many grams of beryllium BeCl 2 are needed to make 125ml of 10 % solutions
Solution:
Concentration in % (w/v) = 100 × (mass solute in g) / (volume solution in mL)
Hence,
10% m/v = 100 × (mass BeCl2 / 125 mL)
mass BeCl2 = 12.5 g
Answer: 12.5 grams of BeCl2 are needed to make 125 mL of 10% solution.
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