Answer to Question #160899 in Chemistry for shelby

Question

For a particular lab experiment, you need 150 mL of a 2.50 M solution of ammonium nitrate. How many grams of NH₄NO₃ will you need for the solution?

Answer 1

Solution:

Molarity = mol solute / solution volume

Hence,

Moles of NH₄NO₃ = Molarity × Solution volume = 2.50 M × 0.15 L = 0.375 mol

Moles = Mass / Molar mass

The molar mass of NH₄NO₃ is 80.043 g mol^-1.

Hence,

Mass of NH₄NO₃ = Moles × Molar mass = 0.375 mol × 80.043 g mol^-1 = 30.016 g = 30 g

Mass of NH₄NO₃ = 30 g

Answer: 30 grams of NH₄NO₃ will you need for the solution.