Question

how many liters of neon gas are in 7 moles of neon gas?

Answer 1

At standard temperature pressure conditions, the volume of $n$ moles of neon gas is:

$V= \frac{nRT}{p}$ ,

where $R$ is the ideal gas constant 8.314 J/(mol K), $T$ is the temperature 273.15 K and $p$ is the pressure 10⁵ Pa. Therefore:

$V = \frac{7·8.314·273.15}{10^5} = 0.159$ m³, or 1590 L.

Answer: at STP conditions, 7 moles of neon gas occupy 1590 L.