Answer to Question #157401 in Chemistry for marrekk

Question

what size container do you need to hold 4.97 mol of N2 gas at STP

Answer 1

Solution:

1^st Solution Path:

At STP, one mole of any gas occupies a volume of 22.4 dm³.

Thus 4.97 mol of N₂ occupies:

(4.97 mol × 22.4 dm³) / 1 mol = 111.33 dm³ = 111.3 dm³

V(container) = 111.3 dm³

2^nd Solution Path:

STP is defined as a temperature of 273.15 K and an absolute pressure of 101.325 kPa.

The Ideal Gas equation (PV = nRT) can be used.

P = 101.325 kPa

V = unknown

n = 4.97 mol

R = 8.314 J⋅K⋅mol⁻¹

T = 273.15 K

Hence,

V = nRT / P

V = (4.97 mol × 8.314 J⋅K⋅mol⁻¹ × 273.15 K) / (101.325 kPa) = 111.39 dm³ = 111.4 dm³

V (container) = 111.4 dm³

Answer: The size container is 111.3 dm³.