2Na+Cl2→2NaCl
When 10.0 g of Cl2 is used, the reaction produced 12.5 grams NaCl. What is the % yield of the reaction?
Use the following molar masses: Cl2=70g/mol and NaCl=58g/mol.
2Na + Cl2 → 2NaCl
The theoretical yield of the reaction:
m(NaCl) = m(Cl2) × 2 Mr(NaCl) / Mr(Cl2) = 10.0 g × 2 × 58 g/mol / 70 g/mol = 16.6 g
As theoretical yield is 16.6 g and actual yield is 12.5 g NaCl, the percent yield equals:
w% = (actual yield / theoretical yield) × 100% = 12.5 g / 16.6 g = 75.3%
Answer: 75.3%
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