n = m/M
m (ZnSO4.H2O) = 27.44/1000 = 0.02744 g
M (ZnSO4.H2O) = 179.49 g/mol
n (ZnSO.H2O) = 0.02744/179.49 = 0.00015 mol
Each mole of matter contains 6.02214076×1023 molecules.
Given amount of ZnSO.H2O is equal to: 0.00015 x 6.02214076×1023 = 1020 molecules.
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