Question #139658
A sample of 0.892 g of potassium chloride (KCl) is dissolved in 54.6 g of water. What is the percent by mass of KCl in this solution?
Calculate the percent by volume of 20 mL of alcohol diluted in water to produce 250mL solution.
1
Expert's answer
2020-10-21T12:48:36-0400

1) %=frac\{};{}Cm(KCl)=m(solute)m(solute)+m(solvent)100Cm (KCl)=\frac{m(solute)}{m(solute)+m(solvent)}⋅100%

%=frac\{};{}Cm(KCl)=0.8920.892+54.6100=1.6percentCm (KCl)=\frac{0.892}{0.892+54.6}⋅100 = 1.6 percent


2) Cv=v(solute)v(solute)+v(solvent)100Cv =\frac{v(solute)}{v(solute)+v(solvent)}⋅100%

Cv(alcohol)=2020+250100=7.4percentCv (alcohol)=\frac{20}{20+250}⋅100=7.4 percent

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS