1) %=frac\{};{}Cm(KCl)=m(solute)m(solute)+m(solvent)⋅100Cm (KCl)=\frac{m(solute)}{m(solute)+m(solvent)}⋅100%Cm(KCl)=m(solute)+m(solvent)m(solute)⋅100
%=frac\{};{}Cm(KCl)=0.8920.892+54.6⋅100=1.6percentCm (KCl)=\frac{0.892}{0.892+54.6}⋅100 = 1.6 percentCm(KCl)=0.892+54.60.892⋅100=1.6percent
2) Cv=v(solute)v(solute)+v(solvent)⋅100Cv =\frac{v(solute)}{v(solute)+v(solvent)}⋅100%Cv=v(solute)+v(solvent)v(solute)⋅100
Cv(alcohol)=2020+250⋅100=7.4percentCv (alcohol)=\frac{20}{20+250}⋅100=7.4 percentCv(alcohol)=20+25020⋅100=7.4percent
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