V1 = 6 L
T1 = 10°C = 283 K
V2 = unknown
T2 = 50°C = 323 K
P = const
Solution:
Since the pressure doesn't change, Charle's law can be used.
Charle's law law can be expressed as: V1/T1 = V2/T2
To find the final volume, solve the equation for V2:
V2 = V1T2 / T1
V2 = (6 L × 323 K) / (283 K) = 6.848 L = 6.85 L
V2 = 6.85 L
Answer: A sample of chlorine gas occupy 6.85 L at 50 °C.
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