Answer to Question #174969 in Physical Chemistry for Cory I Fisher

Question

The initial partial pressures are PA = 0.000 torr, PB = 0.000 torr, and

PC = 150. torr, and the total pressure at equilibrium is 200.0 torr. What are

the values for Kp and Kc at 800. K temperature?

Answer 1

A(g) + B(g) $\leftrightarrow$ C(g)

If total pressure is 200 torr, then P_A = x torr, P_B = x torr, P_C = (150 - x) torr

200 = 2x + (150 - x)

x = 50

Kp = $\dfrac{P_C}{P_AP_B}$ =$\dfrac{100}{50\times50}$ = 0.04 (torr^-1)

Kc = $\dfrac{Kp}{(RT)^{\Delta n}}$ =$\dfrac{0.04}{(8.134\times800)^{-1}}$ = 266.05