Answer to Question #174152 in Physical Chemistry for Surendra

Question

Calculate the specific heat capacity unknown metal.giveen that mass of metal 31.207. Initial temperature of metal 98.2. mass 0f cold water 82.100. initial temperature of cold water and calorimeter 21.8. final temperature of everything 24.0. Give me solution fast

Answer 1

Using energy conservation,

Heat loss by metal = Heat gain by water

$(ms□T)m = (ms□T)w$

31.207×s×(98.2-24.0) = 82.1 × 4.184 × (24.0-21.8)

Heat capacity (s )= [0.326] J/g-°c