Question #173999

100mL 0.5 M NAOH are added to 500 mL 0.1 M h2s04.what are the final concentration of Na+,H+ and SO4 2-?how many miles and how many mol/L of neutralization reaction take place?assume complete dissociation.




1
Expert's answer
2021-03-22T08:01:23-0400

C1V1=C1V2C_1V_1=C_1V_2


=(100mL×0.5M)=500mL×V2=(100mL×0.5M)=500mL×V_2


V2=0.1MV_2=0.1M


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