Question

100mL 0.5 M NAOH are added to 500 mL 0.1 M h2s04.what are the final concentration of Na+,H+ and SO4 2-?how many miles and how many mol/L of neutralization reaction take place?assume complete dissociation.

Answer 1

$C_1V_1=C_1V_2$

$=(100mL×0.5M)=500mL×V_2$

$V_2=0.1M$