Question

During electrolysis of aq. NaCl solution for 6 hours, 11.2 litres of Cl2 gas at STP is evolved at anode. The current
in amperes passing through the cell during electrolysis is

Answer 1

moles of chlorine =$\frac{11.2}{22.4}=0.5 moles$

since n factor of chlorine gas is 2

so 0.5 moles accounts for 1 equivalent

and for 1 equivalent 1 Farad of electricity is required

$96500=I\times6\times60\times60\\I=4.467A$