Solution.
"Al^0 + NO2^- = Al(OH)4^- + NH3"
"Al^0 + 4OH^- = Al(OH)4^- + 3e"
"NO2^- + 5H2O + 6e = NH3 + 7OH^-"
"2Al^0 + NO2^- + OH^- + 5H2O = 2Al(OH)4^- + NH3"
Answer:
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