Saturated concentration = KHxK_HxKHx
9.2 mg per litre = 9.232×10−3=2.875×10−4M\frac{9.2}{32}\times10^{-3}= 2.875\times10^{-4}M329.2×10−3=2.875×10−4M
Percent saturation= 2.8754.609×100=62.37%\frac{2.875}{4.609}\times100=62.37\%4.6092.875×100=62.37%