Saturated concentration= kHxk_HxkHx
=2.2×10−3×0.2095=4.609×10−4M=2.2\times 10^{-3}\times0.2095\\=4.609\times10^{-4}M=2.2×10−3×0.2095=4.609×10−4M
9.2 mg per litre =9.232×10−3=2.875×10−4M=\frac{9.2}{32}\times10^{-3}= 2.875\times10^{-4}M=329.2×10−3=2.875×10−4M
Percent saturation=
2.8754.609×100=62.37%\frac{2.875}{4.609}\times100=62.37\%4.6092.875×100=62.37%
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