Answer to Question #175495 in Organic Chemistry for TUHIN SUBHRA DAS

Question #175495

The cell reaction for a galvanic cell is given below: 

 Zn(s) + 2Ag+

 (aq) →Zn2+ (aq) + 2Ag(s) 

i) Write the half-cell reactions at the anode and the cathode. 

ii) Calculate the value of cell emf under standard conditions; use data from Table 7.1. 

 iii) Will the reaction be spontaneous as written?


1
Expert's answer
2021-03-26T07:50:10-0400

i) Oxidation at anode: "Zn(s) \u2192 Zn^{2+} (aq) + 2e^{\u2212}"


Reduction at cathode: "Ag+ (aq) + e^{\u2212} \u2192 Ag (s)"


ii)Ag: E = +0.80 V

Zn: E = -0.76 V


"E_0cell = E_0cath \u2013 E_0anode = +0.80 \u2013(-0.76) = 1.56 V"


iii)"\u0394G = -nFE"


If "E_0" is positive, ΔG is negative, thus reaction is spontaneous.


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