1.Mg(s) + Fe2+ (aq) + SO42- (aq) = Fe(s) + Mg2+ (aq)+ SO42- (aq) In the reaction represented by thechemical equation below identify which substance loses electrons and which substance gains electrons.
a) Mg gains electrons and Fe2+ loses electrons.
b) Mg loses electrons and Fe2+ gains electrons.
c) Mg2+ gains electrons and Fe loses electrons.
d) Mg2+ loses electrons and Fe gains electrons.
2. In the reaction above which substance is oxidized and which one is reduced.
a) Mg is reduced and Fe2+ is oxidized.
b) Mg2+ is oxidized and Fe2+ is reduced.
c) Mg is oxidized and Fe2+ is reduced.
d) Mg2+ is reduced and Fe is oxidized.
3. In the reaction above which substance is the reducing agent?
a) SO42-
b) Mg
c) Fe2+
d) Fe
1. In this reaction Mg changes to Mg2+ ,so It loses electrons
Fe2+ changes to Fe its means it is gaining electron.
so,option b is correct
2.
Since Mg is losing electron so it is oxidised and Fe2+ is reduced.
So,option b is correct.
3.
Since Mg is oxidised so it is reducing agent.So,option b correct.
Comments
Leave a comment