Answer to Question #172189 in Organic Chemistry for Abdullah

Question #172189

fluoride is a good leaving group in aromatic nucleophilic substitution while it is poor leaving group in SN1 and SN2? Explain


1
Expert's answer
2021-03-17T06:38:27-0400

Its high charge density makes it relatively unpolarizable. The leaving group needs to be polarizable to lower the energy of the transition state.


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