A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. He found that the equilibrium temperature of a mixture of ice and water was 1.2oC on his thermometer. When he added 12.2 g of her sample to the mixture, the temperature, after thorough stirring, fell to –3.0oC. He then poured off the solution through a screen into a beaker. The mass of the solution was 100.5 g. What did he find to be the molar mass of acetone; assuming he made the calculation properly?
mass of acetone added= 12.2 g
mass of solution =100.5 g, moles of acetone=
change inn temp= 4.2
we know that as per depression of freezing point = 1.86
we know that
4.2= 1.86
mass of water= = 93.15
so mass of water was= 93.15 g
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