Question

If molarity of Na2CO3 is 0.05 M at a volume of 25.00 cm3 while the titre value of HCl is 14.00 cm3, calculate the concentration of HCl in mol/dm3. Equation of the reaction is Na2CO3(aq) + 2HCl(aq) →2NaCl(aq) + H2O(l) + CO2(g) Na = 23, Cl = 35.5, C = 12, O = 16, H = 1

Answer 1

C_a= ?

V_a= 14.00cm³

n_a= 2

C_b= 0.05M

V_b= 25.00cm³

n_b=1

C_a= C_bV_bn_a/V_an_b = 0.05 x 25.00 x 2/ 14.00 x 1 = 0.18M