Question

Calculate the heat produced when 6.50x10^3g of sulfur trioxide gas combines with water to produce sulfuric acid.

Answer 1

$Heat Energy ; Q = mc ΔT$

Water has a specific heat capacity of 4,181 joules/kg

Thus;

$Q=6.5Kg×4181J/Kg$

$Q=27,176.5J$ of heat released.