Answer to Question #154661 in Organic Chemistry for Nisarga D P

Question

A galvanic cell is constructed by coupling Ag and Cd electrodes dipped in 0.5M silver nitrate and 0.25M CdSO₄ respectively at 25⁰ C. Write the cell scheme cell reaction, and calculate emf of the cell. Given that SRPs of Ag and Cd are +0.80V and -0.40V respectively.

Answer 1

the cell scheme:

А (–) Сd | Cd²⁺ || Ag⁺ | Ag (+) C

cell reaction:

(–) А: Сd – 2e^- = Сd²⁺

(+) C: Ag⁺ + 1e^- = Ag

E_Cd/Cd²⁺ = –0.40 + (0.059*lg0.25)/2 = –0,418V

E _Ag/Ag⁺ = 0.80 + 0.059*lg0.5 = 0,782V

emf = 0,782 – ( –0,418) = 1,200V